a bus starting from rest moves with a uniform acceleration of 0.1 metre per second square for 2 minutes . find the speed acquired and the distance covered by the body?
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Here, acceleration a = 0.1 ms-2
Time t = 2min = 2 x 60 = 120s
Initial speed u = 0
(a) From Ist equation of motion, speed acquired, v = u + at
= 0 + 0.1 x 120
= 12 ms-2
(b) From IInd equation of motion,
Distance travelled,
image001
= 0.1 x 60 x 120 = 720
Time t = 2min = 2 x 60 = 120s
Initial speed u = 0
(a) From Ist equation of motion, speed acquired, v = u + at
= 0 + 0.1 x 120
= 12 ms-2
(b) From IInd equation of motion,
Distance travelled,
image001
= 0.1 x 60 x 120 = 720
Answered by
4
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➧ u ➾ 0
➧ a ➾ 0.1 m/s²
➧ t ➾ 2 min = 120s
a❱ V ➾ u + at
V ➾ 0.1 × 120
V ➾ 12 ms-¹ ...✔
b❱ v² - u² ➾ 2as
(12)² - (0)² ➾ 2 (0.1)s
s ➾ 720 m ...✔
_________ Thanks...✊
➧ u ➾ 0
➧ a ➾ 0.1 m/s²
➧ t ➾ 2 min = 120s
a❱ V ➾ u + at
V ➾ 0.1 × 120
V ➾ 12 ms-¹ ...✔
b❱ v² - u² ➾ 2as
(12)² - (0)² ➾ 2 (0.1)s
s ➾ 720 m ...✔
_________ Thanks...✊
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