Question

A bus starting from rest moves with a uniform acceleration of 0.1 m/ s for 2 minutes. find the speed acquired, the distance travelled.​

Answer 1

Answer:

v = 12 m / sec and s = 720 m

Explanation:

Given :

Initial velocity u = 0 m / sec

Acceleration a = 0.1 m / sec²

Time t = 2 min = 120 sec

We're asked to find final velocity and distance travelled :

a .

Using first equation :

v = u + a t

Putting values here we get :

= > v = 0 + 0.1 × 120 m / sec

= > v = 12 m / sec

b.

Using third equation :

v² = u² + 2 a s

= > s = ( v² - u² ) / 2 a

Putting values here we get :

= > s = ( 12² - 0² ) / 2 × 0.1 m

= > s = 144 / 2× 0.1

= > s = 72 / 0.1 m

= > s = 720 m

Hence we get required answer!

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find,

(a) Speed acquired,

(b) Distance travelled.

According to the 1st equation of motion,

We know that,

v = u + at

Putting all the value, we get

⇒ v = u + at

⇒ v = 0 + 0.1 × 120

⇒ v = 0.1 × 120

⇒ v = 12 m/s

Hence, Speed acquired finally by the bus is 12 m/s.

Now, we will find the Distance travelled.

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values again, we get

⇒ v² - u² = 2as

⇒ (12)² - (0)² = 2(0.1) s

⇒ 144 = 0.2s

⇒ 144/0.2 = s

⇒ s = 720 m

Hence, the Distance travelled by bus is 720 m.