Question

Derive Taylor's series ​

Answer 1

Answer:

Taylor series can often be derived by doing arithmetic with known Taylor series. sinc(x)=sin(x)/x=x−1+∞∑n=0(−1)nx2n+1(2n+1)! =+∞∑n=0(−1)nx2n(2n+1)!

Answer 2

Answer:

Taylor series can often be derived by doing arithmetic with known Taylor series.

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