Question

. A bus starting from rest moves with a uniform acceleration of 0.2m/s 2 for 5 minutes. Calculate the speed acquired and the distance covered.

Answer 1

Explanation:

u = 0 m/s ( given)

t= 5min = 300 s

a= 0.2 m/s2

using equation v= u+ at

we get v= 60m/s

now for finding distance we can use s= ut + 1/2at2

s= 0×300+ 1/2×0.2×(300)2

s= 9000 m

hope this had helped you

Answer 2

Explanation:

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