Question

A bus starting from rest, moves with a uniform acceleration of 0.1m/s² for 2 minutes. Find:-
i)The speed required
ii)The distance travelled

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Answer 1

Answer:

the distance travelled = 12 m/s

speed required = 720 m

Answer 2

Answer:

Explanation:

Given:-

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find:-

(a) Speed acquired,

(b) Distance traveled.

Formula to be used :-

1st and 3rd equation of motion,

i.e, v = u + at and v² - u² = 2as

Solution:-

Putting all the value, we get

(a) Speed acquired

v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

(b) Distance traveled.

v² - u² = 2as

⇒ (12)² - (0)² = 2(0.1) s

⇒ 144 = 0.2s

⇒ 144/0.2 = s

⇒ s = 720 m

Hence, Speed acquired finally by the bus is 12 m/s.

And Distance traveled by bus is 720 m.