Question

A bus starting from rest moves
with a uniform acceleration of
0.1 m s2 for 2 minutes. Find (a)
the speed acquired, (b) the
distance travelled.​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find,

(a) Speed acquired,

(b) Distance travelled.

According to the 1st equation of motion,

We know that,

v = u + at

Putting all the value, we get

⇒ v = u + at

⇒ v = 0 + 0.1 × 120

⇒ v = 0.1 × 120

⇒ v = 12 m/s

Hence, Speed acquired finally by the bus is 12 m/s.

Now, we will find the Distance travelled.

According to the 3rd equation of motion,

We know that,

v² - u² = 2as

So, putting all the values again, we get

⇒ v² - u² = 2as

⇒ (12)² - (0)² = 2(0.1) s

⇒ 144 = 0.2s

⇒ 144/0.2 = s

⇒ s = 720 m

Hence, the Distance travelled by bus is 720 m.

Answer 2

AnswEr :

Given that a bus starting from rest moves with a uniform acceleration of 0.1 m/s² in 2 minutes.

We have to find a) Speed acquired by bus ; b) Distance travelled by bus.

From the given data we have : Initial speed(u) = 0 m/s². Acceleration (a) = 0.1 m/s². Time (t) = 2 × 60 = 120 seconds.

Now to find speed acquired we will use 1st equation of motion :-

→ v = u + at

Here -

• v : Final speed
• u : Initial speed
• a : Acceleration
• t : Time

Substituting values,

→ v = 0 + 0.1 × 120

→ v = 0 + 12

→ v = 12 m/s

∴ Speed acquired by bus = 12 m/s [Ans : a]

Now to find distance travelled we will use 3rd equation of motion :-

→ s = ut + ½ at²

Where,

• t : Time taken
• u : Initial speed
• a : Acceleration
• s : Distance travelled

Substituting values,

→ s = 0 × 120 + ½ × 0.1 × 120²

→ s = 0 + ½ × 0.1 × 14400

→ s = 7200 × 0.1

→ s = 720 m

∴ Distance travelled by bus = 720 m [Ans : b]