Question

A bus starting from rest moves with a uniform acceleration of 10 cm/s2for 120s.Find the speed acquired and the distance travelled.
fast!!

Answer 1

Answer:

speed acquired  = 1200cm

distance = 72000cm

Explanation:

use the formula v = u+at for speed acquired

use the formula s = ut+1/2at^2 for distance travelled

Answer 2

$\pink{\huge{\underline{\underline{✯Solution:–}}}}$

Initial velocity of the bus u = 0 (bus is at rest)

Acceleration, a = 10 cm/s² = 0.01 m/s²

Time, t = 120 seconds

Let the speed of the bus be ' V '

$\star\:\:\:\bf\large\underline\blue{Formula:—a=v-u/t}$

0.01 = v×0/120

v = 1.2 m/s

As per third law of motion ,

$\star\:\:\:\bf\large\underline\green{v²-u²=2as}$

(1.2)²-(0)² = 2(0.01)s m

s = 72 m

☞︎︎︎ The speed of required by bus = 1.2 m/s

☞︎︎︎ The distance travelled = 72 m

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