Question

A bus starting from rest moves with a uniform acceleration of 0.1 m/s for 2 minutes. Find : (i) the speed acquired, (ii) the distance travelled.​

Answer 1

this question can be solved by proper application of the equations of motion

1. v = u+ at
2. d = ut+ ½at²
3. 2ad = v²-u²

Answer 2

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★ Sᴏʟᴜᴛɪᴏɴ :-

Given ,

• Bus is starting from rest
• Acceleration = 0.1 m/s²
• Time = 2 min = 120s

We need to find ,

• i) Speed acquired
• ii) Distance travelled

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i) Speed acquired

Sol:-

Finding speed using first equation of motion.

• v = u + at

Where

• v → final velocity = ?
• u → Initial Velocity = 0 m/s
• a → acceleration = 0.1 m/s²
• t → time taken = 2min = 120s

Note :- Here , the initial velocity will be zero because the bus is starting from rest .

➛ v = 0 + 0.1 (120)

➛ v = 0 + 12

➛ v = 12 m/s

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ii) Distance travelled

Sol :-

Finding distance travelled using third equation of motion .

S = ut + 1/2 at²

Where,

• S → distance travelled = ?
• u → initial velocity = 0 m/s
• t → time taken = 120s
• a → acceleration = 0.1 m/s²

Substituting the values we have

⇒ S = 0(120) + 1/2 (0.1) (120)²

⇒ S = 1/2 × 1440

⇒ S = 0.5 × 1440

⇒ S = 720 m

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∴ Hence , velocity = 12 m/s & distance travelled = 720m

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