Question

A bus starting from rest moves with a uniform acceleration of 0.1.ms-² for two minutes. find the distance travelled​

Answer 1

Answer:

We will use 2nd equation of motion for this as we know value of a, t and u

a = 0.1ms-²

t = 2 mins = 120 sec

u = 0 ( initially the bus is at rest )

s = ut + 1/2 at²

s = 0×120 + 1/2×0.1×(120)²

s = 1/2 × 0.1 × 14400

s= 720 m

So, the distance travelled by bus in 2 minutes would be 720 m.

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Explanation: