Question

A bus starting from rest moves with a uniform acceleration of 0.1m/s2 for 2minutes. Find speed acquires and distance travelled.​

Answer 1

Acceleration (a) = 0.1ms-2

$Time (t) = 2 minute = 120 second$

(a) The speed acquired:

We know that, v = u + at

$⇒v=0+0.1m/s2×120s⇒v=0+0.1m/s2×120s$

$⇒v=120m/s⇒v=120m/s$

Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

(b) The distance travelled:

Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.(b) The distance travelled:We know that,$s=ut+12at2s=ut+12at2$

$⇒s=0×120s+12×0.1 m$/$s2×(120s)2⇒s=0×120s+12×0.1 m/s2×(120s)2$

$=12×1440m=720m=12×1440m=720m$

Thus, bus will travel a distance of 720 m in the given time of 2 minute.

Answer 2

Given :-

Initial speed of the bus = 0 m/s

Acceleration = 0.1 m/s²

Time taken, t = 2 minutes = 120 s

To Find :-

(a) Speed acquired,

(b) Distance travelled.

Solution :-

Putting all the value, we get

(a) Speed acquired

⇒ v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s