a bus starting from rest moves with a uniform acceleration of 5m/s² for 10 minutes. calculate the speed acquired and the distance moved.
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Answer:
The distance travelled:
S= UT+1/2AT^2The distance travelled:
The distance travelled:We know that
speed acquired:
We know that, v = u + at
⇒v=0+50m/s
v=50m/s
S= UT+1/2AT^2The distance travelled:
S=> 0x10+1/2x5x(10)²
S=> 0+1/2x500
S=> 250m
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