Question

A bus starting from rest moves with a uniform acceleration of 0.1m s-2 minutes. Find (a) the speed acquired (b) the distance travelled

I need the solution..
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Answer 1

Explanation:

Answer: Here we have, Initial velocity (u) = 0

Acceleration (a) = 0.1ms-2

Time (t) = 2 minute = 120 second

(a) The speed acquired:

We know that, v = u + at

⇒v=0+0.1m/s2×120s⇒v=0+0.1m/s2×120s

⇒v=120m/s⇒v=120m/s

Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

(b) The distance travelled:

We know that, s=ut+12at2s=ut+12at2

⇒s=0×120s+12×0.1 m/s2×(120s)2⇒s=0×120s+12×0.1 m/s2×(120s)2

=12×1440m=720m=12×1440m=720m

Thus, bus will travel a distance of 720 m in the given time of 2 minute.

Answer 2

Answer:

Here we have, Initial velocity (u) = 0

Acceleration (a) = 0.1ms-2

Time (t) = 2 minute = 120 second

(a) The speed acquired:

We know that, v = u + at

⇒v=0+0.1m/s2×120s⇒v=0+0.1m/s2×120s

⇒v=120m/s⇒v=120m/s

Thus, the bus will acquire a speed of 120 m/s after 2 minute with the given acceleration.

(b) The distance travelled:

We know that, s=ut+12at2s=ut+12at2

⇒s=0×120s+12×0.1 m/s2×(120s)2⇒s=0×120s+12×0.1 m/s2×(120s)2

=12×1440m=720m=12×1440m=720m

Thus, bus will travel a distance of 720 m in the given time of 2 minute.