Question

a bus starting from rest moves with a uniform acceleration of 0.1m/sec² for 2minutes. find the speed accqired and distance.
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Answer 1

Answer:

$\huge\purple{\mathfrak{Question :-}}$

a bus starting from rest moves with a uniform acceleration of 0.1m/sec² for 2minutes. find the speed accqired and distance.

$\huge\purple{\mathfrak{answer:-}}$

(a) Acceleration

The bus starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-²

Time = 2 minutes = 120 s

Acceleration is given by the equation a=(v-u)/t

Therefore, terminal velocity (v) = (at)+u

= (0.1 m.s-² * 120s) + 0 m.s-²

= 12m.s-¹ + 0 m.s-¹

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-², v = 12 m.s-¹, u = 0 m.s-¹, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =(v² – u²)/2a

=(12² – 0²)/2(0.1)

Therefore, s = 720m.

The speed acquired is 12m.s-¹ and the total distance traveled is 720m.

Explanation:

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Answer 2

Given

• The bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes

To Find :-

• Acceleration and distance travelled

Solution

(a) Acceleration

The bus starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-2

Time = 2 minutes = 120 s

Acceleration is given by the equation a=(v-u)/t

Therefore, terminal velocity (v) = (at)+u

= (0.1 m.s-2 * 120s) + 0 m.s-1

= 12m.s-1 + 0 m.s-1

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-2, v = 12 m.s-1, u = 0 m.s-1, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =(v2 – u2)/2a

=(122 – 02)/2(0.1)

Therefore, s = 720m.

• The speed acquired is 12m.s-1 and the total distance traveled is 720m.

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