Question

A bus starting from rest moves with a uniform acceleration of 0.1m/sec(squared) for 2 min. Find speed and distance.

Answer 1

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♠ Given,

Initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m/s²

Time (t) = 2 min = 120 sec



♠ Then, by first equation of motion,

Final velocity (v) = u + at

$\sf{=⟩ v = 0 + (0.1 \times 120)}$

$\sf{=⟩ v = 0 + 12}$

$\sf{=⟩ v = 12 \: m/s}$



♠ Also, by second equation of motion,

Distance (s) = ut + ½at²

$\sf{=⟩ s = (0 \times 120) + (\frac{1}{2} \times 0.1 \times {120}^{2})}$

$\sf{=⟩ s = 0 + (0.05 \times 14400)}$

$\sf{=⟩ s = 0 + 720}$

$\sf{=⟩ s = 720 \: m}$



♥ •°• The final velocity is 12 m/s and distance travelled is 720 m. ♥
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Thank you... (^_-)