Question

A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find (a) the speed acquired, (b) the distance travelled.

Answer 1

Acceleration =0.1/s^2

Time=2 min

=2 x 60 sec

=120 sec

(a) u=0

v=u+at

v=0.1 x 120

=12m/s

(b) S=ut +1/2 at^2

=1/2 x 0.1 x 120 x 120

= 6 x 120

=720 m

Answer 2

Answer:

Known Terms:-

u = Initial Velocity

v = Final velocity

t = Time

a = Acceleration

s = Distance

Given:-

Initial speed of  bus, u= 0 m/s

Acceleration of bus, a = 0.1 m/s2

Time taken by bus, t = 2 minutes = 60 × 2 = 120 s

To Find:-

(a) The speed acquired

(a) Distance Travelled

Solution:-

(a) The speed acquired

Here, we have to find the Final velocity (v)

Then, we use 1st equation of motion that is v = u + at

⇒ v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

Hence, the speed acquired by bus is 12 m/s.

(a) Distance Travelled

Here, we have to find the Distance travelled (s)

Then, we use 3rd equation of motion that is v² - u²= 2as

⇒ v² - u²= 2as

⇒ (12)2 - (0)2 = 2(0.1) s

⇒ s = 720 m

Hence, Distance Travelled by bus is 720 m.