Question

plz solve it in full steps

Answer 1

c = Speed of light in air → 3 X 10^8 m/s

W → Wavelength

n → Refractive index of the medium = 1.5

W in air = 6000 A = 6 X 10^-7 metres

λ → Frequency in air = c / W in air = 5 X 10^14 Hz

n = W in air / W in the medium

1.5 = 6000 / W in the medium

W in the medium = 4000 A

Magnitude of frequency depends upon the light producing source hence it remains constant throughout ( 5 X 10^14 Hz) .

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Answer 2

Wavelength in air = 6000 A = 6×10^(-7) m

Frequency in air = speed/wavelength= 3×10^8 ÷ (6×10^(-7)) = 5×10^14 Hz

Frequency of the wave won't change when it enters the medium. So frequency in medium will be 5×10^14 Hz.

But wavelength will change.
Refractive index of medium = 1.5
Wavelength in medium = wavelength in air/refractive index = 6000/1.5 = 4000 A

In the medium, frequency will be 5×10^14 Hz and wavelength will be 4000A