A bus starting from rest moves with abuniform acceleration of 0.2m/s^2 for 5 minutes.Calculate the speed acquired and distance moved.Brainliest answer needed.
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Given that:
u=0,a=0.2m/s2 and t=5 min=300 sec
Using equation,
v=u+at
=0+0.2 x 300=60 m/s
again
v^2+u^2=2as
s=v^2+u^2÷2a
s= 60^2-0÷2×0.2
=9000m or 9 km
u=0,a=0.2m/s2 and t=5 min=300 sec
Using equation,
v=u+at
=0+0.2 x 300=60 m/s
again
v^2+u^2=2as
s=v^2+u^2÷2a
s= 60^2-0÷2×0.2
=9000m or 9 km
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