Question

A bus starting from rest moves with uniform acceleration of 0.5 m/s2
for 2 min. find:-
(a) the speed acquired
(b) the distance travelled.

Answer 1

Answer:

 = 0,      a = 0.1 m/sec²        t = 120 sec = 2minutes

equation of motion :  v = u + a t = 0 + 0.10 * 120 = 12 m/sec

s = u t + 1/2 a t² = 0 + 1/2 * 0.10 * 120² = 720 meters

Explanation:

Answer 2

Explanation:

a=0.1m/s

2

and t=2min=120s

(A)v=u+at=0+0.1×120

⟹v=12m/s

(b)s=ut+

2

1

at

2

⟹s=0+

2

1

×0.1×(120)

2

⟹s=720m