A bus starting from rest moves with uniform acceleration of 0.1 metre per second square of 2 minutes calculate the speed required the distance travelled
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when a = 0.1m/s²
t = 2 minutes =120 seconds
therefore, v=u+at (equation of motion :1 )
v=0+(0.1)(120)
v=12m/s
distance : v²=u²+2as (equation of motion :3)
(12)²=0+(2)(0.1)s
144=0.2s
therefore, s=720m
t = 2 minutes =120 seconds
therefore, v=u+at (equation of motion :1 )
v=0+(0.1)(120)
v=12m/s
distance : v²=u²+2as (equation of motion :3)
(12)²=0+(2)(0.1)s
144=0.2s
therefore, s=720m
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