Question

A bus starts from rest accelerates in a straight line at a constant rate 3 ms-2 for 8 seconds. Calculate the distance travelled by the bus during this time interval.

Answer 1

$\textbf{ Hello Mate! }$

Initial Velocity ( u ) = 0

acceleration = $3\:m/{s}^{2}$

Time taken = 8 s

$s = ut + \frac{1}{2} a {t}^{2} \\ s = (0)(8) = \frac{1}{2} (3) {(8)}^{2} \\ s = \frac{1}{2} \times 3 \times 8 \times 8 \\ s = 3 \times 4 \times 8 \\ s = 96 \: m$

$\boxed{ Distance\:travelled\:is\:96m }$

Have great future ahead!

Answer 2

hello everyone

initial velocity (U) = 0.

acceleration = 3ms

time = 8sec

we use motion law formula

S = ut + 1 / 2 at²

S = 0 *8 + 1 /2 * 3 * 8 *8

S = 0 + 4*3*8

S = 96 m

hence answer is 96m

Distance = 96m