The length and breadth of a rectangle are in the ratio of 3:2. If the area of the field is 1350 square cm,find the cost of fencing the field at the rate of 5.50 per square.
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3
let length= 3z
breadth=2z
area = l×b
1350=3z×2z
1350=6z^2
1350/6=z^2
225= z^2
z=5
so
length=3×5=15
breadth =2×5=10
cost of fencing = perimeter ×5.50
= 2(l+b)×5.50
=2(15+10)×5.50
=2(25)×5.50
=50×5.50
=rs250
breadth=2z
area = l×b
1350=3z×2z
1350=6z^2
1350/6=z^2
225= z^2
z=5
so
length=3×5=15
breadth =2×5=10
cost of fencing = perimeter ×5.50
= 2(l+b)×5.50
=2(15+10)×5.50
=2(25)×5.50
=50×5.50
=rs250
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7
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