a bus starts from rest and attains 40km h-1 velocity after 10 sec. calculate the acceleration of the bus in km h -2 and ms-2
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Explanation:
a= v-u/t
10 sec = 1/6 hr
a = 40- 0/ 1/6
= 40*6kmhr^-2
= 240kmhr^-2
in m/sec
40 km/hr = 100/9 m/sec
a=v-u/t
= 100/9 /10
= 10/9 msec^-2v
or 1.11msec^-2
please mark BRAINIEST
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