Question

A bus starts from rest and attains a speed of 36 km / h in 10min while moving with uniform acceleration . Calculate the distance travelled by the bus ?

Answer 1

Answer:

1800

Explanation:

u=0

v=36

t=10

s= u+1/2at^2

s= 0+1/2.36.(10)^2

s=1800

Answer 2

Answer:

3000m

Explanation:

initial velocity,u=0km/h

final velocity,v=36km/h×5/18=10m/s

time,t=10min×60sec=600sec

So let distance travelled be=s

a=v-u/t

a=10-0/600

a=1/60

So,

v²-u²=2as

s=v²-u²/2a

s=(10)²-(0)²/2×1/60

s=100-0/1/30

s=100×30

s=3000m