Question

A bus starts from rest and attains a speed of 36 km/hr in 10 min while moving with uniform acceleration? calculate the acceleration of the bus. ​

Answer 1

★$\color{darkblue}\underline{\underline{\sf Given-}}$

• Speed of bus initially was (u) = 0 m/s
• Speed of bus finally (v) = 36 km/h
• Time (t) = 10 min

★$\color{darkblue}\underline{\underline{\sf To \: Find -}}$

• Acceleration (a

★$\color{darkblue}\underline{\underline{\sf Formula \: Used -}}$

✏ First Equation Of Motion

$\color{violet}\bullet\underline{\boxed{\sf v=u+at}}$

★$\color{darkblue}\underline{\underline{\sf Solution-}}$

$\underline{\sf Convert \: km/h \: to \: m/s-}$

$\implies{\sf v=36\:km/h}$

$\implies{\sf v=36×\dfrac{5}{18}}$

$\color{orange}\implies{\sf v=10\:m/s }$

Now ,

$\underline{\boxed{\sf v=u+at}}$

$\implies{\sf 10=0+a×10}$

$\implies{\sf a=\dfrac{10}{10} }$

$\color{red}\implies{\sf a=1\:m/s^2}$

★$\color{darkblue}\underline{\underline{\sf Answer-}}$

Acceleration of bus is $\color{red}{\sf 1\:m/s^2}$

Answer 2

Given:-

Initial velocity ,u = 0m/s

Final velocity ,v = 36km/h

Time taken ,t = 10min

To Find :-

Acceleration ,a

Solution :-

We have to calculate the acceleration of the bus .

As we know that acceleration is defined as the rate of change in velocity .

Conversion of unit

➻ v = 36×5/18

➻ v = 2×5

➻ v = 10m/s

And,

➻ t = 10×60

➻ t = 600s

Now, calculating the acceleration .

Using Formula

a = v-u/t

substitute the value we get

➻ a = 10-0/600

➻ a = 10/600

➻ a = 1/60

➻ a = 0.0166 ≈ 0.017 m/s²

Hence, the acceleration of the bus will be 0.017 m/s².

So, the required option is (b) 0.017m/s².