a bus starts from rest and attains a velocity of 46m/s after 10 seconds.find the acceleration and the distance travelled in 5 seconds and in 10 seconds.
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1
Given,
Initial velocity is zero, u=0, accelerated by a
1
=2ms
−1
and time t=10sec
v=u+at
v
1
=0+2×10 ⇒v
1
=20ms
−1
In the second event, final velocity v
3
=0, retarded by a
2
=−4ms
−2
0=v
1
−4t
2
t
2
=
4
v
1
=
4
20
=5sec
Displacement, s=ut+
2
1
at
2
s
1
=ut
1
+
2
1
a
1
t
1
2
=0+
2
1
2×10
2
=100m
s
2
=v
1
t
2
+
2
1
a
2
t
2
2
=20×5+
2
1
(−4)×5
2
=50m
Total displacement, s
1
+s
2
=100+50=150m
Total displacement is 150m
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