Question

A bus starts from rest and attains a velocity of a 20 m/s in 8 sec. Find the acceleration produced and distance covered by the bus

Answer 1

Answer:-

• Initial velocity=u=0m/s
• Final velocity=v=20m/s
• Time=t=8s
• Acceleration=a=?
• Distance=s=?

We know that

$\boxed{\sf a=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto a=\dfrac{20-0}{8}$

$\\ \sf\longmapsto a=\dfrac{20}{8}$

$\\ \sf\longmapsto a=2.5m/s^2$

Now

$\boxed{\sf s=ut+\dfrac{1}{2}at^2}$

$\\ \sf\longmapsto s=0(8)+\dfrac{1}{2}\times (2.5)(8)^2$

$\\ \sf\longmapsto s=8+\dfrac{1}{2}\times 2.5(64)$

$\\ \sf\longmapsto s=8+2.5(32)$

$\\ \sf\longmapsto s=8+80$

$\\ \sf\longmapsto s=88m$