Question

A bus starts from rest and gains an
acceleration of 2m/s^2. A man 20m behind the bus
run with a uniform velocity of 1 m/sec. To catch
it. The time in which he catchers the bus is​

Answer 1

Answer:

ANSWER

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒

2

1

at

2

=vt−48

⇒

2

1

(1)t

2

=10t−48

⇒t

2

−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus

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Answer 2

Answer:

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