Question

One fourth of uniform chain of mass 'm' and length
l' is hanging from the end of a horizontal table. The
amount of work done by external agent such that
one sixth is hanging from the edge of the table is
mg/
5mgl
(a)
(b)
288
72
(c)
5mgl
288
(d)
5mgl
576​

Answer 1

Answer:

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Explanation:

W.D =Δ(P.E)

= mass of hanging part × height of COM of hanging part ×g

=

4

m

×

8

L

×g=

32

mgL