Question

A bus starts from rest and moves with a uniform acceleration of 1m/s^2 for 2 min. Calculate i) the speed ii) the distance travelled by the bus.

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As the bus starts from rest)

Acceleration, a = 1 m/s²

Time taken, t = 2 min = 2 × 60 = 120 seconds

To Find,

Final velocity, v = ?

Distance traveled = ?

According to the 1st equation of motion,

We know that

v = u + at

So, putting all the values, we get

⇒ v = u + at

⇒ v = 0 + 1 × 120

⇒ v = 1 × 120

⇒ v = 120 m/s

Hence, the final velocity of bus is 120 m/s.

According to the 3rd equation of motion,

We know that

v² - u² = 2as

So, putting all the values, we get

⇒ v² - u² = 2as

⇒ (0)² - (120)² = 2 × 1 × s

⇒ 14400 = 2s

⇒ 14400/2 = s

⇒ s = 7200 m.

Hence, the distance traveled by bus is 7200 m.

Answer 2

✯✯ QUESTION ✯✯

A bus starts from rest and moves with a uniform acceleration of 1m/s^2 for 2 min. Calculate i) the speed ii) the distance travelled by the bus.

━━━━━━━━━━━━━━━━━━━━

✰✰ ANSWER ✰✰

$\longmapsto\tt{Initial\:Velocity(u)=0}$

$\longmapsto\tt{Acceleration(a)=1{m}^{2}}$

$\longmapsto\tt{Time\:Taken(t)=2m=120\:sec.}$

$\longmapsto\tt{Final\:Velocity=?}$

$\longmapsto\tt{Distance\:Travelled(s)=?}$

➮Now ,

➥Using 1st Equation of Motion : -

$\longmapsto\tt{\large{\boxed{\bold{\bold{\orange{\sf{v=u+at}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{v=(0)+(1)(120)}$

$\longmapsto\tt{v=0+120}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{v}\orange{=}\purple{120m/s}}}$

☛So , The final velocity (v) of the bus is 120m/s..

➥Now ,

➥Using 3rd Equation of Motion : -

$\longmapsto\tt{\large{\boxed{\bold{\bold{\red{\sf{{v}^{2}-{u}^{2}=2as}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{{(120)}^{2}-{(0)}^{2}=2(1)s}$

$\longmapsto\tt{14400=2s}$

$\longmapsto\tt{s=\cancel\dfrac{14400}{2}}$

$\green\longmapsto\:\large\underline{\boxed{\bf\pink{s}\red{=}\orange{7200m.}}}$

☛So , The distance travelled by the bus is 7200m...