Question

A bus starts from rest and moves with a uniform acceleration of 1 m/s2 for 5min calculate speed and distance travelled

Answer 1

hii mate!!

Initial speed = 0
time taken = 5 min = 300 s
let final speed = v

then,
use kinematics equation ,
v = u + at
= 0 + 0.2 × 300 = 60 m/s

and distance travelled = S ( let )
use formula ,

S = ut + 1/2at²
= 0 + 1/2 × 0.2 × (300)²
=0.1 × 90000
=9000 m
= 9 km

hope it helps !! ☺☺☺

Answer 2

Answer:

plz mark as brainlist

Explanation:

v=u+at

v=0+1(500)

v=500m/s

v^2-u^2=2as

500*500=2*1*s

s=250000/2

s=125000