Question

A bus starts from rest. If its speed increases to 20m/sec accelerating at a uniform rate of 2.5m/sec^2, find the time interval.

Answer 1

Answer:

8 seconds

Explanation:

u=0(starts from rest)    v=20m/s    a=2.5m/s²

now using v=u+at;

20=0+2.5×t

t=20÷2.5=8

Answer 2

$\boxed{\rm{\blue{Find \longrightarrow }}}$

Time interval?

$\boxed{\rm{\red{Given \longrightarrow }}}$

• $\sf{Initial \ speed [u] =0m/s}$

• $\sf{ Final Speed [v] = 20m/s}$

• $\sf{ Acceleration [a]= 2.5m/s^2}$

$\boxed{\rm{\orange{solution \longrightarrow }}}$

Formula to be used

$\boxed{\bf{ a= \dfrac{v-u}{t} }}$

Put value in the formula we get,

$\sf{ 2.5= \dfrac{20-0}{t} }$

$\sf{t= \dfrac{20}{2.5}}$

$\sf{t=8 sec}$

$\boxed{\bf{\pink{\underline{ \therefore Time\ interval = 8 sec}}}}$

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