Question

A bus starts from rest.If the acceleration of the bus is 0.5m/s20.5m/s2,what wil be its velocity at the end of 2minute &what distance will it cover during that time?​

Answer 1

Explanation:

Given:

• initial velocity (u) = 0 m/s
• acceleration (a) = 0.5 m/s^2
• time (t) = 2 min = 2 × 60 = 120 seconds

To find:

• final velocity (v) = ?
• distance (s) = ?

Solution:

☆ We know Newton's first kinematic equation i.e, v = u + at

(putting values)...

--> v = 0 + 0.5 × 2

--> v = 1 m/s

☆ We know Newton's second kinematic equation i.e, s = ut + 1/2 × at^2

(putting values)...

--> s = 0 × 2 + 1/2 × 0.5 × (2)^2

--> s = 0 + 1/2 × 0.5 × 4

--> s = 0.5 × 2

--> s = 1 m

Hence, the velocity = 1 m/s & the distance bus traveled in that time = 1 meters.

Hope this helped you dear...