Question

A bus starts from rest . If the acceleration of the bus is 0.5 m/s2, what will be it's velocity at the end of 2 minutes and what distance will it cover during that time?

Answer 1

Explanation:

s=ut+1/2at²

v=?

v=u+at

v=0+0.5x2

v=1m/s²

OK use s=ut+1/at²

s=0+1/2(0.5)(2)²

s=1/2x2

s=1m

Answer 2

Answer:

Explanation:

Given :-

Initial velocity, u = 0 (As bus starts from rest)

Acceleration, a = 0.5 m/s²

Time taken, t = 2 seconds

To Find :-

Final velocity, v = ??

Distance covered, s = ??

Formula to be used :-

1st equation of motion, i.e, v = u + at

2nd equation of motion, i.e, s = ut + 1/2 × at²

Solution :-

Putting all the values, we get

v = u + at

⇒ v = 0 + (0.5) × 2

⇒ v = 1 m/s

Now, distance traveled,

s = ut + 1/2 × at²

⇒ s = 0 × 2 + 1/2 × (0.5) × 4

⇒ s = 1/2 × 2

⇒ s = 1 m.

Hence, the final velocity is 1 m/s and distance covered is 1 m.