Question

A bus starts from rest, picks up velocity of 90km/hr in half minute,calculate uniform acceleration of bus

Answer 1

As acceleration is rate of change of velocity,and according to question here acceleration is uniform hence
a=(( (90*5)/18)-0)/(1/2)*60
a=5/6

Answer 2

The bus starts from rest, therefore, initial velocity(u) = 0 m/s
The final velocity of bus = 90 km/h (v)= 25 m/s
Given time = 1/2 min (t) = 30 s
Acceleration (a) = (v - u)/t
                           = (25 - 0)/30
                           = 25/30
                           = 0.8333 m/s²
The acceleration of the bus = 0.833333 m/s²

Hope this helps you.