A bus starts from rest with aa constant acceleration of 5 m/s25 m/s2 . At the same time a car travelling with a constant velocity 50 m/s50 m/s overtakes and passes the bus. How fast is the bus travelling when they are side by side.
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Answer:
100m/s
Explanation:
UT + 1/2 AT² = 50T
0×T+1/2×5×T² = 50T
5/2 T² = 50T
5/2 T = 50
T = 50×2/5
T = 20 SECONDS
DISTANCE = SPEED × TIME
DISTANCE = 50 × 20
DISTANCE = 1000 METRES
USING 3RD EQUATION OF UNIFORMLY ACCELERATED MOTION,
V² = U² + 2AS
V² = 0² + 2×5×1000
V² = 10×1000
V = √10000
V = 100 M/S
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