Question

A bus starts moving from the position of
rest at a bus stop with uniform acceleration
distance of 95m. Calculate its acceleration
During 10th minute of its motion it Covers​

Answer 1

Answer:

0.05277 m/s square .

Explanation:

u = 0 . s= 95m t= 10 m = 10 × 60s = 600 s

by using -

s = ut + 1/2 at square

95 = 0(600) + 1/2 (a) (600) square

95= 0 + 1/2 (a) (3600)

95 = (a) 1800

a= 95/ 1800

= 19/360

= 0.05277..m/s square .

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