Question

A bus starts moving with an acceleration of 2 m/s ^2. a cyclist 96m behind the bus starts simultaneously towards the bus at 20 m/s. after what time will he be able to overtake the bus

Answer 1

Answer:

8 s is the answer

Velocity of bus V

b

=0 , Velocity of cyclist V

c

=20m/s,

Acceleration of bus a

b

=2m/s

2

Acceleration of cyclist a

c

=0

Relative velocity V

cb

=V

c

−V

b

=20m/s

Relative acceleration a

cb

=a

c

−a

b

=−2m/s

2

Relative separation =96m

Using s=ut+

2

1

at

2

⇒96=20t−

2

1

2t

2

⇒t

2

−20t+96=0

Solving the equation , we get t=8s and t=12s

Hence, after 8s, cyclist will overtake the bus.