Question

a bus starts moving with uniform acceleration from a position of rest. it moves 48 metres in 4s. on applying breaks it stops after covering 24m. Find the deceleration of the bus.

Answer 1

s=ut+1/2at^2
$48 = < 0 > < 4 > + < \frac{1}{2} > < a > < 16 > \\ 48 = 8a \\ a = \frac{48}{8 } \\ a = 6 \\ v = u + at \\ v = 0 + < 6 \times 4 > \\ v = 24 \\ {v}^{2} - {u}^{2} = 2as \\ 0 - {24}^{2} = 2a24 \\ - 24 = 2a \\ a = - 12$