Question

A bus stop is barricaded from the remaining part of the road, by using 50 hollow
cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height
Im. If the outer side of each of the cones is to be painted and the cost of painting is
12 per m', what will be the cost of painting all these cones? (Use i = 3.14 and take
V1.04 = 1.02)​

Answer 1

according to the question

height of cone=1m

radius=.2m

since ,only outer part is to be painted...which means,curved surface area

curved surface area,of cone=πr(l+r)

here,l=√r^2+h^2

l=√1.04=1.02

so curved surface area=3.14(1.02+.2)

=3.14×1.22

=3.83m^2

cost of painting these comes=50×3.83×12=2298

hence ,sum of 2298 will be required ......

don't take tension...mod bhi tera account Bina kisi reason ke delete nhi kr skta...........

be brainly ✌️

Answer 2

Step-by-step explanation:

QUESTION :-

A bus stop is barricaded from the remaining part of the roa

A bus stop is barricaded from the remaining part of the road, by using 50 hollowcones made of recycled cardboard. Each cone has a base diameter of 40 cm and height Im. If the outer side of each of the cones is to be painted and the cost of painting is 12 per m', what will be the cost of painting all these cones? (Use i = 3.14 and taken V1.04 = 1.02)

ANSWER :-

FORMULA :-Curved surface area of cone will be painted=πrl

GIVEN :-

h=1m;

radius= 40 / 2

=20cm

=0.2m

and let l be the slant height,

∴ l ^2 =h ^2 +r ^2

=1 ^2 +0.2 ^2

____________

⇒l = √ 1 + 0.04

= √1.04 = 1.02 (given in question)

SOLUTION :-

⇒Curved surface area of 1 cone=πrl=(3.14×0.2×1.02)m^ 2

=0.64046m ^2

⇒ Curved surface area of 50 cones=50×0.64046=32.028m ^2

Cost of painting 1m ^2= Rs.12

∴ Cost of painting 32.028m ^2

=(12×32.028)=384.336m ^2

≈384.34

∴ Cost of painting 50 cones is Rs.384.84

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@TheStellar ♥️ (Gurjari)