Question

A bus travelling at 20m/s is subjected to steady acceleration of 5m/s2.how long it take to come at rest

Answer 1

u = 20 m/s 

a = 5m/s²

v= u + at 

t = 20 / 5 

t = 4 sec 

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Answer 2

v=20m/s
a= 5m/s^2
u=0

v=u+at
20= 0+5t
20= 5t
t= 20/5
t= 4 sec