Question

A bus travelling at 30 K/m speeds upto 60k/m in 6 seconds. What is its acceleration in m/s2.

Answer 1

For getting acceleration, speed must be in m/s

Hence 30km/hr
= 30 × 5/18
= 150/18
= 50/6
= 25/3m/s

60km/hr
= 60 × 5/18
= 50/3m/s

acceleration = v - u/t

=
$\frac{ \frac{50}{3} - \frac{25}{3} }{6} \\ \\ = \frac{ \frac{25}{3} }{6} \\ = \frac{25}{3} \times \frac{1}{6} \\ = \frac{25}{18} \\ = 1.388888\\ = 1.389$
Hence acceleration = 50m/s²

$\mathfrak{Hope\: it\: helps\: dear\: friend}$ ☺️✌️✌️✌️

Answer 2

Hey friend !!!!!

•°• Here's your answer •°•

Initial Velocity = u = 30km/hr

Final Velocity = v = 60km/hr

Time = t = 6sec

Acceleration = a = ??

$the \: three \: equations \: of \: motion \: are = \\ \\a) v = u + at \\ \\ b) \: s = ut + \frac{1}{2}a {t}^{2} \\ \\ c) \: {v}^{2} = {u}^{2} + 2as$

We can find this by first equation of motion.

But first need to convert the given velocities in m/sec.

$v = 60 \times \frac{5}{18} = \frac{50}{3} \frac{m}{sec} \\ \\ u = 30 \times \frac{5}{18} = \frac{25}{3} \frac{m}{sec}$

Let's solve it ye.

$v = u + at \\ \\ \frac{50}{3} = \frac{25}{3} + a \times 6 \\ \\ \frac{50}{3} - \frac{25}{3} = 6a \\ \\ \frac{25}{3} = 6a \\ \\ \frac{25}{3} \times \frac{1}{6} = a \\ \\ \frac{25}{18} = a \\ \\ a = 1.388888889 \: or \: 1.39$

Hope it satisfies you ☆▪☆

Thanks ^_^

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