Question

A bus travells frist one third distance at the speed of 10kmph
and next one third distance at a speed of 20kmph and at last one third distance at speed of 60kmph the average speed is​

Answer 1

Explanation:

as distance is same then

avg speed = 3×v1×v2×v3/v1v2+ v2v3+v3v1

v1 = 10kmph v2 = 20kmph v3 = 60kmph

avg speed = 3 ×10×20×60/10(20) + 20(60)+60(10)

= 36000/200+1200+600

= 36000/2000

= 18 kmph

therefore , avg speed = 18 kmph

Mark ME the brainliest PLZ follow up