A bus travells frist one third distance at the speed of 10kmph
and next one third distance at a speed of 20kmph and at last one third distance at speed of 60kmph the average speed is
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Explanation:
as distance is same then
avg speed = 3×v1×v2×v3/v1v2+ v2v3+v3v1
v1 = 10kmph v2 = 20kmph v3 = 60kmph
avg speed = 3 ×10×20×60/10(20) + 20(60)+60(10)
= 36000/200+1200+600
= 36000/2000
= 18 kmph
therefore , avg speed = 18 kmph
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