A bus travels a distance of 180 km with a speed of 60 km/hr and returns with the speed of 30 km/hr. Calculate the average speed for the entire journey
Answers
Given that, distance (d) = 180 km and speed of bus (s) = 60 km/hr.
Also given that, the bus returns with a speed of 30 km/h.
The distance is the same throughout i.e. 180 km.
Assume that the bus starts from point A to B (A→B) and covers a distance of 180 km with a speed of 60 km/hr.
Now, the bus returns to it's actual point A (from B to A point) with a speed of 30 km/hr.So, the total distance covered = 180 + 180 = 360 km
Average velocity = (Total distance covered)/(Total time taken)
Also time = distance/speedAccording to question,
→ 20/(180/60 + 180/30)
→ 360/(3 + 6)
→ 360/(9)
→ 40 km/hr
Given :-
- Car Travel 180km at a speed of 60km/h.
- Return at Speed of 30km/h.
To Find :-
- Average Speed for whole journey ?
Solution :-
→ Speed of Car while going forward = 60km/h
→ Distance covered = 180km.
→ Time taken = (Distance / speed) = (180/60) = 3 Hours.
And,
→ Speed of Car while going Returning = 30km/h
→ Distance covered = 180km.
→ Time taken = (Distance / speed) = (180/30) = 6 Hours.
So,
→ Total Distance Covered by car = 180 + 180 = 360km.
→ Total Time taken = 3 + 6 = 9 hours.
Therefore ,
→ Average Speed = (Total Distance) / (Total Time)
→ Average Speed = (360) / 9 = 40km/h.
Hence, Average Speed of Car for the whole journey is 40km/h.
_________________
Direct Formula :-
☛ Average Speed = ( 2 * S₁ * S₂ ) / (S₁ + S₂)
Here, we Have :-
➼ S₁ = 60km/h.
➼ S₂ = 30km/h.
So,
☞ Average Speed = (2 * 60 * 30) / (60 + 30)
☞ Average Speed = (3600) / (90)
☞ Average Speed = 40km/h.