A bus travels at a speed of 50 km/h for 12 minutes & then at a speed of 40 km/h for the next 18 minutes. Total Kita hu distance covered by the bus during this time is - (1) 20 km (2) 22 km (3) 24 km 14) 28 km
Answers
Answer:
Correct Question-:
A bus travels at a speed of 50 km/h for 12 min and then at a speed of 40km/h for next 18 min . Find the total distance covered by the bus during these times .
AnswEr-:
The total distance covered by bus is 22 km
Explanation
Given ,
A bus travels at a speed of 50 km/h for 12 min and then at a speed of 40km/h for next 18 min .
To Find ,
The total distance covered by the bus .
Solution -:
As , we know that ,
\boxed{\purple{\sf{Distance \: = \: Speed × Time }}}
Distance=Speed×Time
There are two cases -:
In 1st case
The bus travels at a speed of 50 km/h for 12 min .
~ Distance Covered = Speed × Time
Time = 12 min = 12/60 hrs [ Converted into hours ]
Speed = 50 km/h
Now ,
= 》 12/60 × 50
= 》1/5 × 50
= 》 10 km
Therefore,
In 1st Case it covers distance of 10 km .
In 2nd case
The bus travels at a speed of 40 km/h for 18 min .
~ Distance Covered = Speed × Time
Time = 18 min = 18/60 hrs [ Converted into hours ]
Speed = 40 km/h
Now ,
= 》 18/60 × 40
= 》18/3 × 2
= 》 6 × 2
= 》 12 km
Therefore,
In 2nd Case it covers distance of 12 km
Then,
~ Total distance covered by bus is = Distance covered in 1st case + Distance Covered in 2nd case
Here ,
In 2nd Case it covers distance of 12 km
In 1st Case it covers distance of 10 km .
Now ,
= 》 10 km + 12 km
= 》 22 km
Hence ,
The total distance covered by bus is 22 km