Question

a bus travels at a speed of 50 kmh for 12 min and then at a speed of 40kmh for next 18 min . total distace covered by the bus during this time​

Answer 1

Correct Question-:

• A bus travels at a speed of 50 km/h for 12 min and then at a speed of 40km/h for next 18 min . Find the total distance covered by the bus during these times .

AnswEr-:

• The total distance covered by bus is 22 km

Explanation

Given ,

• A bus travels at a speed of 50 km/h for 12 min and then at a speed of 40km/h for next 18 min .

To Find ,

• The total distance covered by the bus .

Solution -:

As , we know that ,

$\boxed{\purple{\sf{Distance \: = \: Speed × Time }}}$

There are two cases -:

1. In 1st case

• The bus travels at a speed of 50 km/h for 12 min .

~ Distance Covered = Speed × Time

• Time = 12 min = 12/60 hrs [ Converted into hours ]
• Speed = 50 km/h

Now ,

• = 》 12/60 × 50
• = 》1/5 × 50
• = 》 10 km

Therefore,

• In 1st Case it covers distance of 10 km .

In 2nd case

• The bus travels at a speed of 40 km/h for 18 min .

~ Distance Covered = Speed × Time

• Time = 18 min = 18/60 hrs [ Converted into hours ]
• Speed = 40 km/h

Now ,

• = 》 18/60 × 40
• = 》18/3 × 2
• = 》 6 × 2
• = 》 12 km

Therefore,

In 2nd Case it covers distance of 12 km

Then,

~ Total distance covered by bus is = Distance covered in 1st case + Distance Covered in 2nd case

Here ,

• In 2nd Case it covers distance of 12 km
• In 1st Case it covers distance of 10 km .

Now ,

• = 》 10 km + 12 km
• = 》 22 km

Hence ,

• The total distance covered by bus is 22 km .

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