Math, asked by rajalakshmimd85, 6 hours ago

please answer my question tennetiraj sir.​

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Answers

Answered by Parthkr
3

Answer:

154

Step-by-step explanation:

Let x = 10a + b and y = 10b + a

x² - y² = m²

10b + a .. (10a + b)²(10b + a)² = m²

:. (10a+b+10b+ a)(10a + b - 10b a) = m²

11(a+b)9(a - b) = m²

:.99 (a + b)(a - b) = m

²

Since a and bare digits from 1 to 9, a + b = 11 and a - b = 1 is the only

a = 6 and b = 5 possibility for m to be an integer.

⇒ x = 65, y = 56, m = 33

:.x+y+m= 65+56 +33 = 154

Answered by tennetiraj86
2

Step-by-step explanation:

Given :-

Let x and y be the two digits numbers such that y is obtained by the reversing the digits of x and they also satisfy x²-y² = m² for some positive integers m.

To find :-

Find the value of x+y+m ?

Solution :-

Given that

x and y are two digits numbers

Let x = 10a+b

On squaring both sides then

=> x² = (10a+b)²

=> x² = 100a²+20ab+b² -----------(1)

given that

y is obtained by reversing the digits of x

Therefore, y = 10b+a

On squaring both sides then

=> y² = (10b+a)²

=> y² = 100b²+20ab+a² ---------(2)

On Subtracting (2) from (1) then

=>x²-y²

=(100a²+20ab+b²)-(100b²+20ab+a²)

=>x²-y² = 100a²+20ab+b²-100b²-20ab-a²

=>x²-y² = 100a²-a²-100b²+b²

=> x²-y² = (100-1)a²+(-100+1)b²

=> x²-y² = 99a²-99b²

=> x²-y² = 99(a²-b²) --------------(3)

According to the given problem

Given condition is x²-y² = m² -------(4)

From (3)&(4)

=> 99(a²-b²) = m² ---------(5)

The product of 99 and a²-b² is equal to the square number m²

=> 9×11(a²-b²) = m²

=> 3² × 11 (a²-b²) = m²

To get perfect square a²-b² should be 11

=> 3²×11(11)= m²

=> 3²×11² = m² ,a perfect square number

So , a²-b² = 11

=> (a+b)(a-b) = 11

=> (a+b)(a-b) = 11×1

=>(a+b)(a-b) = (6+5)(6-5)

On comparing both sides then

a = 6

b = 5

Now x = 10a+b = 10(6)+5 = 65

y = 10b+a = 10(5)+6 = 50+6 = 56

The two digits numbers are 65 and 56

From (4)

x²-y² = m²

=> (65)²-(56)² = m²

=> 4225-3136 = m²

=> 1089 = m²

=> m² = 1089

=> m² = 33²

=> m = 33

The value of m = 33

The value of x+y+m

On Substituting the values of x,y and m then

=>x+y+m = 65+56+33

=> x+y+m = 154

Therefore, x+y+m = 154

Answer:-

The value of x+y+m for the given problem is 154

Used formulae:-

  • (a+b)(a-b) = a²-b²

  • The numbers are written as the product of two equal numbers is called a perfect square number.
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