Question

can someone please help for this​

Answer 1

option D is the answer

2NO(g)+Br2(g)⟶2NOBr(g)

ΔH°=ΔHP−ΔHR

ΔH°=−23KJ/mol=−ve

We also know that activation enrgy always has a positive value and is always at a higher energy level than the reactants or products.

Hence for the above reaction, the correct pathway diagram is (D)