Question

a bus was moving with a speed of 54 kilometre per hour on applying brakes it stopped in 8 seconds calculate the acceleration​

Answer 1

${\huge{\bf{\green{Solution-:}}}}$

${\sf{Initial~Speed(u)~=\sf\frac{54km}{hr}}}$

$\implies$ ${\sf{54×\sf\frac{1000m}{3600s}}}$

$\implies$ ${\sf{54×\sf\frac{5}{18}}}$

$\implies$ ${\sf{15m/s}}$

${\tt{\orange{(1km=1000m~and~1~hr=60~mins=60×60~seconds=36~seconds)}}}$

${\sf{\blue{Time=8~seconds}}}$

${\sf{\blue{Final~Velocity(V)=0}}}$

${\sf{\orange{We~know~That:}}}$

$\implies$ ${\sf{v=u+at}}$

$\implies$ ${\sf{15+a×8}}$

$\implies$ ${\sf{15+8a}}$

$\implies$ ${\sf{a=\sf\frac{-15}{8}m/s^2}}$

${\sf{\orange{Accelatation=-15/8~m/s^2}}}$

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