a bus weight 10000 kg is moving with speed of 36km/h 'how much regarding force is required to stop the bus in a distance 50m
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12
initial velocity(u)=36km/hr=36*5/18=10m/s
final velocity(v)=0m/s
distance(s)=50m
acceleration=a
according to second equation of motion:-
2as=v^2-u^2
50*2*a=0-(10)^2
100a=-100
a=-100/100
a= -1m/s^2
we know that:-
mass=10000kg
acceleration= -1m/s^2
force= mass*acceleration
force=10000*-1
force=-10000N
or, the retarding force= 10000N
final velocity(v)=0m/s
distance(s)=50m
acceleration=a
according to second equation of motion:-
2as=v^2-u^2
50*2*a=0-(10)^2
100a=-100
a=-100/100
a= -1m/s^2
we know that:-
mass=10000kg
acceleration= -1m/s^2
force= mass*acceleration
force=10000*-1
force=-10000N
or, the retarding force= 10000N
Answered by
9
Initial velocity u = 10m/s
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