a buss travelled a total distance as it covered its journey in consecutive one fourth distance with speed 6 km per hour 50 km per hour 70 kilometre per hour respectively calculate the average speed of was for entire journey
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Answer:
8.53Km/hr
Step-by-step explanation:
Let the total distance be X.
The bus traveled X/4 distance with speed 6km/hr.
Therefore time required to travel X/4 distance=(X/4)÷6 = X/24.
The bus traveled the next X/4 distance with speed 50km/hr.
Therefore time required to travel X/4 distance=(X/4)÷50 = X/200
The bus traveled next X/4 distance with speed 70km/hr.
Therefore time required to travel X/4 distance=(X/4)÷70 = X/280
Thus total distance traveled by bus= X/4+X/4+X/4 =3X/4
Total time taken= X/24 +X/200+ X/280 = (175+21+15)X/2400=211X/2400
Therefore average speed of the journey=(3X/4)÷(211X/2400)=(3X×2400)÷(4×211X)=8.53km/hr
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